Project Euler Problem 6
This turned out to be really easy
Problem:
The sum of the squares of the first ten natural numbers is,
1**2 + 2**2 + ... + 10**2 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)**2 = 55**2 = 3025
Hence the difference between the sum of the squares of the first ten natural
numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred
natural numbers and the square of the sum.