Project Euler Problem 30
This one was tricky because the last number was significantly higher than I
thought it would be.
Problem:
Surprisingly there are only three numbers that can be written as the sum of
fourth powers of their digits:
1634 = 1**4 + 6**4 + 3**4 + 4**4
8208 = 8**4 + 2**4 + 0**4 + 8**4
9474 = 9**4 + 4**4 + 7**4 + 4**4
As 1 = 1**4 is not a sum it is not included.
The sum of these numbers is 1634 + 8208 + 9474 = 19316.
Find the sum of all the numbers that can be written as the sum of fifth powers
of their digits.